0=-9t^2+776

Solution for 0=-9t^2+776 equation:

0=-9t^2+776

We move all terms to the left:

0-(-9t^2+776)=0

We add all the numbers together, and all the variables

-(-9t^2+776)=0

We get rid of parentheses

9t^2-776=0

a = 9; b = 0; c = -776;
Δ = b2-4ac
Δ = 02-4·9·(-776)
Δ = 27936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{27936}=\sqrt{144*194}=\sqrt{144}*\sqrt{194}=12\sqrt{194}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{194}}{2*9}=\frac{0-12\sqrt{194}}{18}
=-\frac{12\sqrt{194}}{18}
=-\frac{2\sqrt{194}}{3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{194}}{2*9}=\frac{0+12\sqrt{194}}{18}
=\frac{12\sqrt{194}}{18}
=\frac{2\sqrt{194}}{3}
$